Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems - Page 33: 21a


1.1 m/s

Work Step by Step

To find the average velocity we need to find the total displacement over the time period and divide by the total time elapsed. Since the period in question is from t = 2 to t =8 we know that the time elapsed is 6 minutes. To find the total displacement we know that there are two segments: 1) Segment 1 is from t =0 to t =5 where the man stands still and so displacement = 0 2) Segment 2 is from t = 5 to t =10 where the man walks at a speed of 2.20 m/s From t = 2 to t = 5, the man travels 0m ( he is standing still) From t = 5 to t =8, a total of 3 minutes or 180 seconds, we need to find the man's displacement. He is traveling at 2.20m/s so 2.20m/s * 180s = 396 meters. Therefore he travels 396 + 0 = 396 meters in 6 minutes, or 360 seconds. His average velocity is 396m/360s = 1.1m/s
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