# Chapter 2 - Motion Along a Straight Line - Problems - Page 33: 22b

$m/s^3$

#### Work Step by Step

The position is given by $x=ct^2−bt^3$where x is in meters and t is in time. Since x is in meters, then we know that each of the terms on the right side (since they are subtracted), must have the same units, and must also be in meters. Since we have $bt^3$ and we know that $t^3$ will have units of $s^3$ and we know that overall $bt^3$ must have units of meters, then we have the following: $m = b*s^3$ and therefore b has units of $m/s^3$

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