## Fundamentals of Physics Extended (10th Edition)

Published by Wiley

# Chapter 2 - Motion Along a Straight Line - Problems: 17b

#### Answer

$18.0$ cm/s

#### Work Step by Step

Average velocity : $v_{avg}=\displaystyle \frac{\Delta x}{\Delta t}=\frac{x_{2}-x_{1}}{t_{2}-t_{1}}$ Instantaneous velocity: $v(t)=\displaystyle \frac{d}{dt}x(t)$ --------------------------------------- $v(t)=\displaystyle \frac{d}{dt}x(t)= \displaystyle \frac{d}{dt}(9.75+1.50t^{3})$ $=3\cdot 1.50t^{2}=4.50t^{2}$ (cm/s) At t=$2.00$, $v(2.00)=4.50(2.00)^{2}$ cm/s$=18.0$ cm/s

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