Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems: 22h

Answer

$v_{(3)}=-36\frac{m}{s}$

Work Step by Step

We need to differentiate $x=3t^2-2t^3$ to find $v$: Therefore, $v=\frac{dx}{dt}=6t-6t^2$ For $t=3s$ $v_{(3)}=6(3)-6(3)^2=-36\frac{m}{s}$
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