Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 442: 98a

Answer

$K=1.0\times10^2\frac{N}{m}$

Work Step by Step

According to Hook's law; $F=Kx$ This can be rearranged as; $K=\frac{F}{x}$ Given that, $F=w=20N$ Hence, $K=\frac{w}{x}$ We plug in the known values to obtain: $K=\frac{20}{0.20}=100=1.0\times10^2\frac{N}{m}$
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