Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 442: 106b

Answer

$m=0.20$ kg

Work Step by Step

$T=2\pi\sqrt\frac{m}{K}$ After squaring both sides and re-arranging, we obtain: $m=(\frac{T}{2\pi})^2K$ From graph, we find that: $T=0.20s$ We plug in the known values in the formula to obtain: $m=(\frac{0.20}{2(3.1416)})^2(200)$ $m=0.20$ kg
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