Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 442: 107

Answer

$K=7\times 10^2\frac{N}{m}$

Work Step by Step

We can find mass $m$ as: $m=\frac{0.108}{6.02\times10^{23}}=1.8\times 10^{-25}$ kg We know that: $f=\frac{1}{2\pi}\sqrt\frac{K}{m}$ This simplifies to: $K=(2\pi f)^2\times m$ We plug in the known values to obtain: $K=(2\times3.1416\times 10^{13})^2\times 1.8\times 10^{-25}$ $K=7\times 10^2\frac{N}{m}$
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