Answer
$T = 0.449~s$
Work Step by Step
We can find the period:
$T = 2\pi \sqrt{\frac{m}{k}}$
$T = 2\pi \sqrt{\frac{10.0~N/9.80~m/s^2}{200.0~N/m}}$
$T = 0.449~s$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 15 - Oscillations - Problems - Page 442: 105a
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