Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 442: 102b

Answer

$25$ oscillations

Work Step by Step

We know that the formula to be used here is: $T=2\pi \sqrt{\frac{m}{k}}$ Substituting the values in the formula above, T is: $T=2\pi \sqrt{\frac{0.80kg}{200N/m}}=0.397s$ Oscillations completed in ten seconds is found through the formula: $\frac{10 s}{0.397s}=25$ oscillations
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