Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 442: 106c

Answer

$-0.20$ m.

Work Step by Step

Since the velocity of the object is zero at $t=0$ s, the object is either at its maximum displacement or negative maximum displacement. The slope of the velocity graph at $t=0$ s is positive, therefore, the acceleration and force must be positive. For the force to be positive, the position must be negative. Therefore, the position is the negative maximum displacement, $-0.20$ m.
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