Answer
$4.0J$
Work Step by Step
Since energy is conserved, the maximum kinetic energy is equal to the maximum potential energy;
$$K_{e,max}=U_{e,max}=\frac{1}{2}kx^2=\frac{1}{2}(200 N/m)(0.20m)^2=4.0 J$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 15 - Oscillations - Problems - Page 442: 106e
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