Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 442: 104b

Answer

$0.136J$

Work Step by Step

The lost energy can be found as: $\Delta E=E_o-E_f$ The formula can be rewritten as: $E_o-E_f=\frac{1}{2}kA_o^2-\frac{1}{2}kA_f^2=\frac{1}{2}k(A_o^2-A_f^2)$ Substituting the values in this formula to find the lost energy; $\frac{1}{2}k(A_o^2-A_f^2)=\frac{1}{2}(10.0N/m)((.250m)^2-(.188m)^2)=0.136J$
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