Answer
$K_a=10^{-3.88}$
Work Step by Step
$pH=\frac{1}{2}(pC_a+pK_a)$
$2.44=\frac{1}{2}(-log(0.10)+pK_a)$
$pK_a=4.88-1=3.88$
$pK_a=-log(K_a)$
$K_a=10^{-3.88}$
Chemistry: The Central Science (13th Edition)
by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.
Published by
Prentice Hall
ISBN 10:
0321910419
ISBN 13:
978-0-32191-041-7
Chapter 16 - Acid-Base Equilibria - Exercises - Page 718: 16.51
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
