Answer
$pH \approx 1.523$
Work Step by Step
1. Find the concentration of $HCl$ after the dilution:
$C_i * V_i = C_f * V_f$
$1 * 0.015 = C_f * 0.500$
$C_f = \frac{0.015}{0.500}$
$C_f = 0.030M$
2. Since $HCl$ is a strong acid:
$[HCl] = [H^+] = 0.030M$
3. Calculate the pH:
$pH = -log[H^+]$
$pH = -log(0.030)$
$pH \approx 1.523$
