Answer
$[H^+]$: Between $6.310 \times 10^{-6}$ and $2.512\times10^{-6}$.
$[OH^-]$: Between $3.981 \times 10^{-9}$ and $1.585\times10^{-8}$.
Work Step by Step
$[H^+] = 10^{-pH}$
1. If the pH is between 5.2 and 5.6, the [H+] is between:
$[H^+] = 10^{-5.2} = 6.310 \times 10^{-6}M$
$[H^+] = 10^{-5.6} = 2.512 \times 10^{-6}M$
2. And the pOH:
pH = 14 - pOH
pOH = 14 - 5.2 = 8.8
pOH = 14 - 5.6 = 8.4
3. Finally, the [OH-] should be between:
$[OH^-] = 10^{-pOH}$
$[OH^-] = 10^{-8.8}$ = $1.585 \times 10^{-9}M$
$[OH^-] = 10^{-8.4}$ = $3.981 \times 10^{-9}M$
