Answer
$[H+]= 2.2\times10^-11 M$
Work Step by Step
$$[H+][OH-]=1.0\times10^{-14}$$
$[H+][.00045]=(1.0\times10^-14)$
$[H+]=(1.0\times10^-14)/[.00045]$
$[H+]=(2.2\times10^-11) M $
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