Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 718: 16.29b



Work Step by Step

$$[H+][OH-]=1.0\times10^{-14}$$ $[H+][8.8\times10^{-9}]=(1.0\times10^{-14})$ $[H+]=(1.0\times10^{-14})/[8.8\times10^{-9}]$ $[H+]=(1.4\times10^{-6}) M $
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