Answer
When the pH variates by 0.5, the [H+] change by approximately 0.31623 times.
Work Step by Step
$[H^+] = 10^{-pH}$
$[H^+] = 10^{-(pH + 0.5)}$
$[H^+] = 10^{-pH}\times10^{-0.5}$
$[H^+] \approx 10^{-pH} \times 0.31623$
Chemistry: The Central Science (13th Edition)
by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.
Published by
Prentice Hall
ISBN 10:
0321910419
ISBN 13:
978-0-32191-041-7
Chapter 16 - Acid-Base Equilibria - Exercises - Page 718: 16.33b
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
