Answer
$[H^+] = 10^{-8}$, it's a basic solution.
Work Step by Step
1. Knowing that [OH-] is 100 times greater than [H+], and [H+] times [OH-] = $10^{-14}$:
$[OH^-] = 100 \times [H^+]$
$ [H^+] \times [OH^-] = 10^{-14}
$
2. Use the substitution method, to find the value of [H+]:
$ [H^+] \times (100\times[H^+]) = 10^{-14} $
$ 100\times[H^+]^2 = 10^{-14}$
$[H^+]^2 = 10^{-16}$
$[H^+] = 10^{-8}$
3. Now that you have the concentration, find the pH of the solution.
$pH = -log[H^+]$
$pH = -log(10^{-8})$
$pH = 8$
4. Because pH > 7, the solution is considered basic.
