Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 718: 16.46a

Answer

$[OH^-] = 0.182M$ $pH = 13.26$

Work Step by Step

1. Since KOH is a strong base: $[OH^-] = [KOH] = 0.182M$ 2. Now, calculate the pOH, and then the pOH of the solution: $pOH = -log[OH^-]$ $pOH = -log( 0.182)$ $pOH = 0.74$ $pH + pOH = 14$ $pH + 0.74 = 14$ $pH = 13.26$
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