Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 718: 16.43a

Answer

pH of 2.07

Work Step by Step

Find pH of $8.5\times10^{-3}$ Molarity HBr $$-log([H+])=pH$$ $-log([8.5\times10^{-3}])=pH$ $pH=2.07$
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