Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 718: 16.50b


$H{CO_3}^-(aq) + H_2O(l) {CO_3}^{2-}(aq) + H^+(aq)$ $H{CO_3}^-(aq) + H_2O(l) {CO_3}^{2-}(aq) + H_3O^+(aq)$ $Ka = \frac{[{CO_3}^{2-}][H^+]}{[HC{O_3}^-]}$

Work Step by Step

An acid will react with water to produce $H^+(H_3O^+)$ and his conjugate base. $H{CO_3}^-(aq) + H_2O(l) {CO_3}^{2-}(aq) + H^+(aq)$ To find the Ka equation: $Ka = \frac{[Products]}{[Reactants]}$ or $Ka = \frac{[H^+][A^-]}{[HA]}$ $Ka = \frac{[{CO_3}^{2-}][H^+]}{[HC{O_3}^-]}$
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