Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic: 95a

Answer

This is a redox reaction. Li acts as a reducing agent and $O_{2}$ acts as an oxidizing agent.

Work Step by Step

In a redox reaction, there is a change in oxidation number. Li's oxidation number changes from 0 to +2. Since there is an increase in the oxidation number, it gets oxidized. Hence, it acts as a reducing agent. $O_{2}$'s oxidation number changes from 0 to -2 which shows that there is a decrease in the oxidation number. This means that $O_{2}$ gets reduced. Hence, it acts as an oxidizing agent.
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