Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 189: 91d

$H; +1$ , $S: -2$

The oxidation state of H is always +1. The oxidation state of group 6A nonmetals, like S, is usually $-2$. This works out because there are 2 H atoms in $H_{2}S$ so the sum of the charges is $2(+1)+(-2)$ which is 0.