Answer
Complete ionic equation:
$Na^+(aq) + OH^-(aq) + HC_2H_3O_2(aq) --\gt H_2O(l) + Na^+(aq) + C_2H_3O_2^-(aq)$
Net ionic equation:
$OH^-(aq) + HC_2H_3O_2(aq) --\gt H_2O(l) + C_2H_3O_2^-(aq)$
Work Step by Step
1. Balance the equation:
$NaOH(aq) + HC_2H_3O_2(aq) --\gt H_2O(l) + NaC_2H_3O_2(aq)$
It is already balanced.
2. For the strong electrolytes in aqueous state, separate the ions:
$NaOH$ and $NaC_2H_3O_2$: Strong electrolytes. (Completely dissociated in water).
$Na^+(aq) + OH^-(aq) + HC_2H_3O_2(aq) --\gt H_2O(l) + Na^+(aq) + C_2H_3O_2^-(aq)$
- This is the balanced complete ionic equation.
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3. Remove the spectator ions:
- Remove the ions that appear unchanged after the reaction.
$Na^+$ doesn't react.
$OH^-(aq) + HC_2H_3O_2(aq) --\gt H_2O(l) + C_2H_3O_2^-(aq)$
- This is the balanced net ionic equation.
