Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 189: 90c

Answer

$$HC_2H_3O_2(aq) + NaHSO_3(aq) \longrightarrow SO_2(g) + H_2O(l) + NaC_2H_3O_2$$

Work Step by Step

1. This reaction has a sulfite and an acid as its reactants. Thus, it will produce $SO_2(g)$, $H_2O(l)$ and a salt made of the other ions: $$HC_2H_3O_2(aq) + NaHSO_3(aq) \longrightarrow SO_2(g) + H_2O(l) + Salt$$ The remaining ions are: $Na^{+}$ and $C_2H_3{O_2}^-$, therefore, the salt is $NaC_2H_3O_2$: $$HC_2H_3O_2(aq) + NaHSO_3(aq) \longrightarrow SO_2(g) + H_2O(l) + NaC_2H_3O_2$$ 2. Now, balance the equation. The equation is already balanced.
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