Answer
$(NH_{4})_{2}SO_{4}(aq)+ SrCl_{2}(aq)\ -->\ SrSO_{4}(s)+ 2(NH_{4})Cl(aq)$
Work Step by Step
$SrSO_{4}$ is not soluble in water so a precipitation reaction occurs. Add a two before $(NH_{4})Cl$ to balance the $NH_{4}$ and $Cl$.
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