Answer
$H_{2}SO_{4}(aq)+ Ca(OH)_{2}(aq)\ -->\ 2H_{2}O(l)+CaSO_{4}(s)$
Work Step by Step
The acid and base neutralize each other to form $H_{2}O$. $CaSO_{4}$ is not soluble so it precipitates out of solution when formed. To balance the equation add a 2 to the $H_{2}O$ as there are two $H^{+}$ and $OH{-}$ ions in the reactions forming two $H_{2}O$ molecules.