Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 189: 85a

Answer

$H_{2}SO_{4}(aq)+ Ca(OH)_{2}(aq)\ -->\ 2H_{2}O(l)+CaSO_{4}(s)$

Work Step by Step

The acid and base neutralize each other to form $H_{2}O$. $CaSO_{4}$ is not soluble so it precipitates out of solution when formed. To balance the equation add a 2 to the $H_{2}O$ as there are two $H^{+}$ and $OH{-}$ ions in the reactions forming two $H_{2}O$ molecules.
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