Answer
$Li_{2}SO_{4}(aq)+ Pb(C_{2}H_{3}O_{2})_{2}(aq)\ -->\ PbSO_{4}(s)+ 2LiC_{2}H_{3}O_{2}(aq)$
Work Step by Step
$PbSO_{4}$ is not soluble in water so a precipitation reaction occurs. Add a two to the $LiC_{2}H_{3}O_{2}$ to balance the $Li^{+}$ and $C_{2}H_{3}O_{2}^{-}$.
