Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 189: 93a

Answer

$+2$

Work Step by Step

O normally has an oxidation state of $-2$ and the molecule $CrO$ is neutral so the sum of the oxidation states must be 0. This means the oxidation state of Cr must be $+2$ as $(-2)+(+2)=0$
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