Answer
$2NaCl(aq)+ Pb(C_{2}H_{3}O_{2})_{2}(aq)\ -->\ PbCl_{2}(s)+ 2NaC_{2}H_{3}O_{2}(aq)$
Work Step by Step
$PbCl_{2}$ is not soluble in water so a precipitation reaction occurs. Add a 2 to the $NaCl$ and $NaC_{2}H_{3}O_{2}$ to balance the $Na^{+}$, $Cl^{-}$, and $C_{2}H_{3}O_{2}^{-}$.
