Answer
$H_{2}SO_{4}(aq)+ 2NaOH(aq)\ -->\ 2H_{2}O(l)+ Na_{2}SO_{4}(aq)$
Work Step by Step
The acid and base neutralize each other to form $H_{2}O$. To balance the equation, add a 2 to the $NaOH$ as there are two $Na^{+}$ ions in the products. Then add a 2 to the $H_{2}O$ as there are two $H^{+}$ and $OH{-}$ ions in the reactions forming two $H_{2}O$ molecules.