Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 189: 90b

Answer

$$HCl(aq) + KHCO_3(aq) \longrightarrow CO_3(g) + H_2O(l) + KCl(aq)$$

Work Step by Step

1. This reaction has a carbonate and an acid as its reactants. Thus, it will produce $CO_3(g)$, $H_2O(l)$ and a salt made of the other ions: $$HCl(aq) + KHCO_3(aq) \longrightarrow CO_2(g) + H_2O(l) + Salt$$ The remaining ions are: $K^{+}$ and $Cl^-$, therefore, the salt is $KCl$: $$HCl(aq) + KHCO_3(aq) \longrightarrow CO_2(g) + H_2O(l) + KCl(aq)$$ 2. Now, balance the equation. The equation is already balanced.
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