Answer
$2NaCl(aq)+ Hg_{2}(C_{2}H_{3}O_{2})_{2}(aq)\ -->\ Hg_{2}Cl_{2}(s)+ 2NaC_{2}H_{3}O_{2}(aq)$
Work Step by Step
$Hg_{2}Cl_{2}$ is not soluble in water so a precipitation reaction occurs. Add a 2 before $NaCl$ to balance the $Cl$. Add another two in front of $NaC_{2}H_{3}O_{2}$ to balance the $Na$ and $C_{2}H_{3}O_{2}$.
