Answer
$C: -4$ , $H: +1$
Work Step by Step
The oxidation state of H is usually $+1$ and $CH_{4}$ is a neutral molecule so the oxidation state of all its atoms must equal 0. This means the oxidation state of C is $-4$ because $4(+1)+(-4)=0$.
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 189: 92d
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