Answer
$Cr(NO_{3})_{3}(aq)+ Na_{3}PO_{4}(aq)\ -->\ CrPO_{4}(s)+ 3NaNO_{3}(aq)$
Work Step by Step
$CrPO_{4}$ is not soluble in water so a precipitation reaction occurs. Add a 3 to the $NaNO_{3}$ to balance the $Na$ and $NO_{3}$.
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