# Chapter P - Section P.7 - Equations - Exercise Set - Page 106: 64

$\left\{-4, 4\right\}$

#### Work Step by Step

Add 1 on both sides of the equation to obtain: $3x^2 = 48$ Divide 3 on both sides of the equation to obtain: $x^2=16$ Take the square root of both sides to obtain: $x = \pm \sqrt{16} \\x=\pm \sqrt{4^2} \\x = \pm 4$ Thus, the solution set of the given equation is $\left\{-4, 4\right\}$.

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