## Precalculus (6th Edition) Blitzer

$\left\{-4, 7\right\}$
RECALL: $|x|=a \longrightarrow x=a \text{ or } x = -a$ Use the rule above to obtain: $2x-3 = 11 \text{ or } 2x-3 = -11$ Solve each equation to obtain: $2x = 11+3 \text{ or } 2x = -11 +3 \\2x = 14 \text{ or } 2x =-8 \\x = \frac{14}{2} \text{ or } x = \frac{-8}{2} \\x=7 \text{ or } x = -4$ Thus, the solution set is $\left\{-4, 7\right\}$.