## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter P - Section P.7 - Equations - Exercise Set - Page 106: 46

#### Answer

$\left\{-4, 7\right\}$

#### Work Step by Step

RECALL: $|x|=a \longrightarrow x=a \text{ or } x = -a$ Use the rule above to obtain: $2x-3 = 11 \text{ or } 2x-3 = -11$ Solve each equation to obtain: $2x = 11+3 \text{ or } 2x = -11 +3 \\2x = 14 \text{ or } 2x =-8 \\x = \frac{14}{2} \text{ or } x = \frac{-8}{2} \\x=7 \text{ or } x = -4$ Thus, the solution set is $\left\{-4, 7\right\}$.

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