Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set: 48

Answer

$\left\{-3, 4\right\}$

Work Step by Step

Divide 3 on both sides of the equation to obtain: $|2x-1|=7$ RECALL: $|x|=a \longrightarrow x=a \text{ or } x = -a$ Use the rule above to obtain: $2x-1 = 7 \text{ or } 2x-1 = -7$ Solve each equation to obtain: $2x = 7+1 \text{ or } 2x = -7 +1 \\2x = 8 \text{ or } 2x =-6 \\x = \frac{8}{2} \text{ or } x = \frac{-6}{2} \\x=4 \text{ or } x = -3$ Thus, the solution set is $\left\{-3, 4\right\}$.
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