Precalculus (6th Edition) Blitzer

$\dfrac{1}{2}$
Subtract $3$ on both sides of the equation to obtain: $|2x-1|=0$ RECALL: $|a|=0 \longrightarrow a=0$ Use the rule above with $a=2x-1$ to obtain: $2x-1 = 0 \\2x = 1 \\x =\frac{1}{2}$ Thus, the solution to the given equation is $\dfrac{1}{2}$.