Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set: 74

Answer

$x=-3\pm\sqrt {14}$

Work Step by Step

$x^2 + 6x - 5 = 0$ $x^2 + 6x+9=14$ $(x+3)^2=14$ $x+3=\pm\sqrt {14}$ $x=-3\pm\sqrt {14}$
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