Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set - Page 106: 62


$\left\{-3, 3\right\}$

Work Step by Step

Divide 5 on both sides of the equation to obtain: $x^2=9$ Take the square root of both sides to obtain: $x = \pm \sqrt{9} \\x=\pm \sqrt{3^2} \\x=\pm 3$ Thus, the solution set of the given equation is $\left\{-3, 3\right\}$.
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