## Precalculus (6th Edition) Blitzer

Solution set = $\displaystyle \{-\frac{4}{5}, 4\}$
$2\displaystyle \left| 4-\frac{5}{2}x\right|+6=18\qquad$ ... subtract 6 ... isolate the absolute value bracket $2\displaystyle \left| 4-\frac{5}{2}x\right|=12\qquad$ ... divide with 2 $\displaystyle \left| 4-\frac{5}{2}x\right|=6\qquad$ ... remove absolute value $\left.\begin{array}{cccclll} 4-\frac{5}{2}x=6 & /\times 2 & or & 4-\frac{5}{2}x=-6 & /\times 2\\ 8-5x=12 & /-8 & & 8-5x=-12 & /-8\\ -5x=4 & /\div(-5) & & -5x=-20 & /\div(-5)\\ x=-4/5 & & & x=4 & \end{array}\right.$ Solution set = $\displaystyle \{-\frac{4}{5}, 4\}$