Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set - Page 106: 54



Work Step by Step

Subtract $4$ on both sides of the equation to obtain: $|3x-2|=0$ RECALL: $|a|=0 \longrightarrow a=0$ Use the rule above with $a=3x-2$ to obtain: $3x-2 = 0 \\3x = 2 \\x =\frac{2}{3}$ Thus, the solution to the given equation is $\dfrac{2}{3}$.
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