Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set - Page 106: 3

Answer

$x = -12$

Work Step by Step

$\frac{x}{4}$ = 2 + $\frac{x - 3}{3}$ LCD = 12 12($\frac{x}{4}$) = 12(2 + $\frac{x - 3}{3}$) 3x = 12($\frac{6 + x - 3}{3}$) 3x = 12($\frac{3 + x}{3}$) 3x = 4(3 + x) 3x = 12 + 4x 3x - 4x = 12 -x = 12 x = -12
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