Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set: 71


$x=3\pm\sqrt {20}$

Work Step by Step

$x^2 - 6x - 11 = 0$ $x^2-6x+9=20$ $(x-3)^2=20$ $x-3=\pm\sqrt {20}$ $x=3\pm\sqrt {20}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.