## Precalculus (6th Edition) Blitzer

$\left\{-\frac{5}{3}, 3\right\}$
Divide 2 on both sides of the equation to obtain: $|3x-2|=7$ RECALL: $|x|=a \longrightarrow x=a \text{ or } x = -a$ Use the rule above to obtain: $3x-2 = 7 \text{ or } 3x-2 = -7$ Solve each equation to obtain: $3x = 7+2 \text{ or } 3x = -7 +2 \\3x = 9 \text{ or } 3x =-5 \\x = \frac{9}{3} \text{ or } x = \frac{-5}{3} \\x=3 \text{ or } x = -\frac{5}{3}$ Thus, the solution set is $\left\{-\frac{5}{3}, 3\right\}$.