Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set - Page 106: 102


Solution set = $\{-6,-1\}$

Work Step by Step

Use the square root property: If $u^{2}=d$ then $u=\pm\sqrt{d}$ Here, $u=2x+7, \quad d=25,\quad\sqrt{d}=5$ Apply the property $2x+7=\pm 5 \quad$ ... add $-7$ to both sides $ 2x=-7\pm 5\quad$ ... divide with $2$ $x=\displaystyle \frac{-7\pm 5}{2}\Rightarrow\left\{\begin{array}{l} x=\frac{-7-5}{2}=-6,\\ \\ x=\frac{-7+5}{2}=-1 \end{array}\right.$ Solution set = $\{-6,-1\}$
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