Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set - Page 105: 12

Answer

Solution set = $\{1\}.$

Work Step by Step

Multiply both sides with the LCD, 12 $ 12 \left[\displaystyle \frac{x+1}{4}\right]=12 \left[ \dfrac{1}{6}+\dfrac{2-x}{3}\right]\quad$ ... distribute and simplify $ 3(x+1)=2+4(2-x)\quad$ ... distribute and simplify $3x+3=2+8-4x$ $3x+3=10-4x \quad$ ... add $4x-3$ to both sides $3x+4x=10-3$ $7x=7$ $x=1$ Solution set = $\{1\}.$
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