Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A52: 121

Answer

$ r=\dfrac{S-a}{S}$

Work Step by Step

Multiply both sides by $1-r$. $S(1-r)=(1-r)\cdot \dfrac{a}{1-r}$ Simplify by cancelling common factors. $S(1-r)=a$ Use distributive property. $S-Sr=a$ Subtract $S$ from both sides. $S-Sr-S=a-S$ Simplify. $-Sr=a-S$ Divide both sides by $-S$. $\dfrac{-Sr}{-S}=\dfrac{a-S}{-S}$ Simplify. $r=\dfrac{S-a}{S}$
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